Question
Answer
$$(6-2i)\cdot(2-3i)=6i^2-22i+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6-2i)\cdot(2-3i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12-18i-4i+6i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6i^2-22i+12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{6-2i}\right) $ by each term in $ \left( 2-3i\right) $. $$ \left( \color{blue}{6-2i}\right) \cdot \left( 2-3i\right) = 12-18i-4i+6i^2 $$ |
| ② | Combine like terms: $$ 12 \color{blue}{-18i} \color{blue}{-4i} +6i^2 = 6i^2 \color{blue}{-22i} +12 $$ |
This page was created using
Complex Expression calculator