Answer
$$(5i-2)\cdot(4-3i)=-15i^2+26i-8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(5i-2)\cdot(4-3i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}20i-15i^2-8+6i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-15i^2+26i-8\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{5i-2}\right) $ by each term in $ \left( 4-3i\right) $. $$ \left( \color{blue}{5i-2}\right) \cdot \left( 4-3i\right) = 20i-15i^2-8+6i $$ |
| ② | Combine like terms: $$ \color{blue}{20i} -15i^2-8+ \color{blue}{6i} = -15i^2+ \color{blue}{26i} -8 $$ |
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