$(5 i - 2) \cdot (4 - 3 i) = - 15 i^{2} + 26 i - 8$

Explanation

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$(5 i - 2) \cdot (4 - 3 i) \overset{◯}{1} 20 i - 15 i^{2} - 8 + 6 i \overset{◯}{2} - 15 i^{2} + 26 i - 8$
①	Multiply each term of $(5 i - 2)$ by each term in $(4 - 3 i)$ . $(5 i - 2) \cdot (4 - 3 i) = 20 i - 15 i^{2} - 8 + 6 i$
②	Combine like terms: $20 i - 15 i^{2} - 8 + 6 i = - 15 i^{2} + 26 i - 8$

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(5i−2)⋅(4−3i)=−15i2+26i−8

$(5 i - 2) \cdot (4 - 3 i) = - 15 i^{2} + 26 i - 8$