$(4 x^{5} + y^{5})^{2} = 16 x^{10} + 8 x^{5} y^{5} + y^{10}$

Explanation

$(4 x^{5} + y^{5})^{2} \overset{◯}{1} 16 x^{10} + 8 x^{5} y^{5} + y^{10}$
①	Find $(4 x^{5} + y^{5})^{2}$ using formula. $(A + B)^{2} = A^{2} + 2 \cdot A \cdot B + B^{2}$ where $A = 4 x^{5}$ and $B = y^{5}$ . $(4 x^{5} + y^{5})^{2} = (4 x^{5})^{2} + 2 \cdot 4 x^{5} \cdot y^{5} + (y^{5})^{2} = 16 x^{10} + 8 x^{5} y^{5} + y^{10}$

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(4x5+y5)2=16x10+8x5y5+y10

$(4 x^{5} + y^{5})^{2} = 16 x^{10} + 8 x^{5} y^{5} + y^{10}$