Answer
$$(4+4i)\cdot(1-2i)=-8i^2-4i+4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4+4i)\cdot(1-2i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4-8i+4i-8i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-8i^2-4i+4\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4+4i}\right) $ by each term in $ \left( 1-2i\right) $. $$ \left( \color{blue}{4+4i}\right) \cdot \left( 1-2i\right) = 4-8i+4i-8i^2 $$ |
| ② | Combine like terms: $$ 4 \color{blue}{-8i} + \color{blue}{4i} -8i^2 = -8i^2 \color{blue}{-4i} +4 $$ |
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