Question
Answer
$$4+3i-(8-12i)=15i-4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4+3i-(8-12i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4+3i-8+12i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}15i-4\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 8-12i \right) = -8+12i $$ |
| ② | Combine like terms: $$ \color{blue}{4} + \color{red}{3i} \color{blue}{-8} + \color{red}{12i} = \color{red}{15i} \color{blue}{-4} $$ |
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