$(4 - 3 i) \cdot (2 + i) = - 3 i^{2} - 2 i + 8$

Explanation

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$(4 - 3 i) \cdot (2 + i) \overset{◯}{1} 8 + 4 i - 6 i - 3 i^{2} \overset{◯}{2} - 3 i^{2} - 2 i + 8$
①	Multiply each term of $(4 - 3 i)$ by each term in $(2 + i)$ . $(4 - 3 i) \cdot (2 + i) = 8 + 4 i - 6 i - 3 i^{2}$
②	Combine like terms: $8 + 4 i - 6 i - 3 i^{2} = - 3 i^{2} - 2 i + 8$

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(4−3i)⋅(2+i)=−3i2−2i+8

$(4 - 3 i) \cdot (2 + i) = - 3 i^{2} - 2 i + 8$