Combine like terms:

$$ \color{blue}{3} + \color{blue}{45} = \color{blue}{48} $$

$$ 9 \cdot 48 = 432 $$

Multiply $ \color{blue}{3} $ by $ \left( 2+34\right) $ $$ \color{blue}{3} \cdot \left( 2+34\right) = 6+102 $$

$$ 3+6\cdot(2+3) = 3 \cdot \color{blue}{\frac{ 1 }{ 1}} + 12+18 \cdot \color{blue}{\frac{ 1 }{ 1}} = \frac{3+12+18}{1} $$

Simplify numerator

$$ \color{blue}{3} + \color{red}{12} + \color{red}{18} = \color{red}{33} $$

Divide both the top and bottom numbers by $ \color{orangered}{ 4 } $.

Remove 1 from denominator.

Add $432$ and $ \dfrac{33}{49} $ to get $ \dfrac{ \color{purple}{ 21201 } }{ 49 }$.

Step 1: Write $ 432 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator.

Step 2: To add fractions they must have the same denominator.
We can create a common denominator by multiplying the first fraction by $\color{blue}{ 49 }$.

$$ \begin{aligned} 432+ \frac{33}{49} & \xlongequal{\text{Step 1}} \frac{432}{\color{red}{1}} + \frac{33}{49} = \frac{ 432 \cdot \color{blue}{ 49 }}{ 1 \cdot \color{blue}{ 49 }} + \frac{ 33 }{ 49 } = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ \color{purple}{ 21168 } }{ 49 } + \frac{ \color{purple}{ 33 } }{ 49 }=\frac{ \color{purple}{ 21201 } }{ 49 } \end{aligned} $$

Subtract $ \dfrac{21201}{49} $ from $ \dfrac{1}{27} $ to get $ \dfrac{ \color{purple}{ -572378 } }{ 1323 }$.

To subtract fractions they must have the same denominator.
We can create a common denominator by multiplying the first fraction by $ \color{blue}{ 49 }$ and the second by $\color{blue}{ 27 }$.

$$ \begin{aligned} \frac{1}{27} - \frac{21201}{49} & = \frac{ 1 \cdot \color{blue}{ 49 }}{ 27 \cdot \color{blue}{ 49 }} - \frac{ 21201 \cdot \color{blue}{ 27 }}{ 49 \cdot \color{blue}{ 27 }} = \\[1ex] &=\frac{ \color{purple}{ 49 } }{ 1323 } - \frac{ \color{purple}{ 572427 } }{ 1323 }=\frac{ \color{purple}{ -572378 } }{ 1323 } \end{aligned} $$