$(3 - 5 y i)^{2} = 25 i^{2} y^{2} - 30 i y + 9$

Explanation

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$(3 - 5 y i)^{2} \overset{◯}{1} 9 - 30 i y + 25 i^{2} y^{2} \overset{◯}{2} 25 i^{2} y^{2} - 30 i y + 9$
①	Find $(3 - 5 i y)^{2}$ using formula. $(A - B)^{2} = A^{2} - 2 \cdot A \cdot B + B^{2}$ where $A = 3$ and $B = 5 i y$ . $(3 - 5 i y)^{2} = 3^{2} - 2 \cdot 3 \cdot 5 i y + (5 i y)^{2} = 9 - 30 i y + 25 i^{2} y^{2}$
②	Combine like terms: $25 i^{2} y^{2} - 30 i y + 9 = 25 i^{2} y^{2} - 30 i y + 9$

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(3−5yi)2=25i2y2−30iy+9

$(3 - 5 y i)^{2} = 25 i^{2} y^{2} - 30 i y + 9$