Answer
$$(3-4i)\cdot(-3+2i)=-8i^2+18i-9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3-4i)\cdot(-3+2i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-9+6i+12i-8i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-8i^2+18i-9\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3-4i}\right) $ by each term in $ \left( -3+2i\right) $. $$ \left( \color{blue}{3-4i}\right) \cdot \left( -3+2i\right) = -9+6i+12i-8i^2 $$ |
| ② | Combine like terms: $$ -9+ \color{blue}{6i} + \color{blue}{12i} -8i^2 = -8i^2+ \color{blue}{18i} -9 $$ |
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