$(3 + 5 j) \cdot (3 + 2 j) = 10 j^{2} + 21 j + 9$

Explanation

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$(3 + 5 j) \cdot (3 + 2 j) \overset{◯}{1} 9 + 6 j + 15 j + 10 j^{2} \overset{◯}{2} 10 j^{2} + 21 j + 9$
①	Multiply each term of $(3 + 5 j)$ by each term in $(3 + 2 j)$ . $(3 + 5 j) \cdot (3 + 2 j) = 9 + 6 j + 15 j + 10 j^{2}$
②	Combine like terms: $9 + 6 j + 15 j + 10 j^{2} = 10 j^{2} + 21 j + 9$

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(3+5j)⋅(3+2j)=10j2+21j+9

$(3 + 5 j) \cdot (3 + 2 j) = 10 j^{2} + 21 j + 9$