Question
Answer
$$\dfrac{2-5i}{1-3i}=\dfrac{17+i}{10}$$
Explanation
| $$ \begin{aligned}\frac{2-5i}{1-3i}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{17+i}{10}\end{aligned} $$ | |
| ① | Divide $ \, 2-5i \, $ by $ \, 1-3i \, $ to get $\,\, \dfrac{17+i}{10} $. ( view steps ) |
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