Answer
$$\frac{2-3i}{-8-i}=\frac{-1+2i}{5}$$
Explanation
| $$ \begin{aligned}\frac{2-3i}{-8-i}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-1+2i}{5}\end{aligned} $$ | |
| ① | Divide $ \, 2-3i \, $ by $ \, -8-i \, $ to get $\,\, \dfrac{-1+2i}{5} $. ( view steps ) |
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