$(1 + 5 i) \cdot (1 - 5 i) = - 25 i^{2} + 1$

Explanation

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$(1 + 5 i) \cdot (1 - 5 i) \overset{◯}{1} 1 - 5 i + 5 i - 25 i^{2} 1 - 5 i + 5 i - 25 i^{2} \overset{◯}{2} - 25 i^{2} + 1$
①	Multiply each term of $(1 + 5 i)$ by each term in $(1 - 5 i)$ . $(1 + 5 i) \cdot (1 - 5 i) = 1 - 5 i + 5 i - 25 i^{2}$
②	Combine like terms: $1 - 5 i + 5 i - 25 i^{2} = - 25 i^{2} + 1$

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(1+5i)⋅(1−5i)=−25i2+1

$(1 + 5 i) \cdot (1 - 5 i) = - 25 i^{2} + 1$