Answer
$$(14-2i)\cdot(7+12i)=-24i^2+154i+98$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(14-2i)\cdot(7+12i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}98+168i-14i-24i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-24i^2+154i+98\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{14-2i}\right) $ by each term in $ \left( 7+12i\right) $. $$ \left( \color{blue}{14-2i}\right) \cdot \left( 7+12i\right) = 98+168i-14i-24i^2 $$ |
| ② | Combine like terms: $$ 98+ \color{blue}{168i} \color{blue}{-14i} -24i^2 = -24i^2+ \color{blue}{154i} +98 $$ |
This page was created using
Complex Expression calculator