$(13 + 7 i)^{2} = 182 i + 120$

Explanation

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$(13 + 7 i)^{2} \overset{◯}{1} 169 + 182 i + 49 i^{2} \overset{◯}{2} 169 + 182 i - 49 \overset{◯}{3} 182 i + 120$
①	Find $(13 + 7 i)^{2}$ using formula. $(A + B)^{2} = A^{2} + 2 \cdot A \cdot B + B^{2}$ where $A = 13$ and $B = 7 i$ . $(13 + 7 i)^{2} = 1 3^{2} + 2 \cdot 13 \cdot 7 i + (7 i)^{2} = 169 + 182 i + 49 i^{2}$
②	$49 i^{2} = 49 \cdot (- 1) = - 49$
③	Combine like terms: $182 i + 169 - 49 = 182 i + 120$

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(13+7i)2=182i+120

$(13 + 7 i)^{2} = 182 i + 120$