$(125 + 125 i)^{2} = 31250 i$

Explanation

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$(125 + 125 i)^{2} \overset{◯}{1} 15625 + 31250 i + 15625 i^{2} \overset{◯}{2} 15625 + 31250 i - 15625 \overset{◯}{3} 31250 i$
①	Find $(125 + 125 i)^{2}$ using formula. $(A + B)^{2} = A^{2} + 2 \cdot A \cdot B + B^{2}$ where $A = 125$ and $B = 125 i$ . $(125 + 125 i)^{2} = 12 5^{2} + 2 \cdot 125 \cdot 125 i + (125 i)^{2} = 15625 + 31250 i + 15625 i^{2}$
②	$15625 i^{2} = 15625 \cdot (- 1) = - 15625$
③	Combine like terms: $31250 i + 15625 - 15625 = 31250 i$

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(125+125i)2=31250i

$(125 + 125 i)^{2} = 31250 i$