Answer
$$-x^2-4x+1-(2x^2+9)=-3x^2-4x-8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-x^2-4x+1-(2x^2+9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-x^2-4x+1-2x^2-9 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-3x^2-4x-8\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 2x^2+9 \right) = -2x^2-9 $$ |
| ② | Combine like terms: $$ \color{blue}{-x^2} -4x+ \color{red}{1} \color{blue}{-2x^2} \color{red}{-9} = \color{blue}{-3x^2} -4x \color{red}{-8} $$ |
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