Answer
$$(-5i)(-x)^2=-5ix^2$$
Explanation
| $$ \begin{aligned}(-5i)(-x)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(-5i)\cdot1x^2 \xlongequal{ } \\[1 em] & \xlongequal{ }-5ix^2\end{aligned} $$ | |
| ① | $$ \left( -x \right)^2 = (-1)^2x^2 = x^2 $$ |
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