$(- 4 - 8 i) \cdot (3 + i) = - 8 i^{2} - 28 i - 12$

Explanation

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$(- 4 - 8 i) \cdot (3 + i) \overset{◯}{1} - 12 - 4 i - 24 i - 8 i^{2} \overset{◯}{2} - 8 i^{2} - 28 i - 12$
①	Multiply each term of $(- 4 - 8 i)$ by each term in $(3 + i)$ . $(- 4 - 8 i) \cdot (3 + i) = - 12 - 4 i - 24 i - 8 i^{2}$
②	Combine like terms: $- 12 - 4 i - 24 i - 8 i^{2} = - 8 i^{2} - 28 i - 12$

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(−4−8i)⋅(3+i)=−8i2−28i−12

$(- 4 - 8 i) \cdot (3 + i) = - 8 i^{2} - 28 i - 12$