Answer
$$(-3+i)\cdot(8-2i)=-2i^2+14i-24$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-3+i)\cdot(8-2i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-24+6i+8i-2i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-2i^2+14i-24\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-3+i}\right) $ by each term in $ \left( 8-2i\right) $. $$ \left( \color{blue}{-3+i}\right) \cdot \left( 8-2i\right) = -24+6i+8i-2i^2 $$ |
| ② | Combine like terms: $$ -24+ \color{blue}{6i} + \color{blue}{8i} -2i^2 = -2i^2+ \color{blue}{14i} -24 $$ |
This page was created using
Complex Expression calculator