$\frac{- 2 j + 6}{j} (- 2 j - 2) = \frac{4 j ^{2} - 8 j - 12}{j}$

Explanation

\frac{- 2 j + 6}{j} (- 2 j - 2) \overset{◯}{1} \frac{4 j ^{2} - 8 j - 12}{j}

①

Multiply $\frac{- 2 j + 6}{j}$ by $- 2 j - 2$ to get $\frac{4 j ^{2} - 8 j - 12}{j}$ .

Step 1: Write $- 2 j - 2$ as a fraction by putting $1$ in the denominator.

Step 2: Multiply numerators and denominators.

Step 3: Simplify numerator and denominator.

\frac{- 2 j + 6}{j} \cdot - 2 j - 2 Step 1 \frac{- 2 j + 6}{j} \cdot \frac{- 2 j - 2}{1} Step 2 \frac{( - 2 j + 6 ) \cdot ( - 2 j - 2 )}{j \cdot 1} = Step 3 \frac{4 j ^{2} + 4 j - 12 j - 12}{j} = \frac{4 j ^{2} - 8 j - 12}{j}

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j−2j+6​(−2j−2)=j4j2−8j−12​

$\frac{- 2 j + 6}{j} (- 2 j - 2) = \frac{4 j ^{2} - 8 j - 12}{j}$