$(- 11 - 7 i) \cdot (2 + 6 i) = - 42 i^{2} - 80 i - 22$

Explanation

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$(- 11 - 7 i) \cdot (2 + 6 i) \overset{◯}{1} - 22 - 66 i - 14 i - 42 i^{2} \overset{◯}{2} - 42 i^{2} - 80 i - 22$
①	Multiply each term of $(- 11 - 7 i)$ by each term in $(2 + 6 i)$ . $(- 11 - 7 i) \cdot (2 + 6 i) = - 22 - 66 i - 14 i - 42 i^{2}$
②	Combine like terms: $- 22 - 66 i - 14 i - 42 i^{2} = - 42 i^{2} - 80 i - 22$

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(−11−7i)⋅(2+6i)=−42i2−80i−22

$(- 11 - 7 i) \cdot (2 + 6 i) = - 42 i^{2} - 80 i - 22$