Answer
$$\frac{(1-2i)z+2i}{z-2i}=\frac{z-2iz+2i}{z-2i}$$
Explanation
| $$ \begin{aligned}\frac{(1-2i)z+2i}{z-2i}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{z-2iz+2i}{z-2i}\end{aligned} $$ | |
| ① | $$ \left( \color{blue}{1-2i}\right) \cdot z = z-2iz $$ |
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